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08-06-2009, 07:38 PM | #1 |
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Simple Math Equation shortcut help
I remember there was an easy way or a short cut method of figuring this out but I just can't remember, maybe some of you guys can remember back to your high school days?
So solve this equation: (5/((x+1)^1)+(5/((x+1)^2)+(5/((x+1)^3).....+(5/((x+1)^60) = 50 find X Wasn't there a shortcut method to solving this really easily? Its like on the tip of my tongue and it's driving me insane lol |
08-06-2009, 07:41 PM | #2 |
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OH FUCK!
its also on the tip of my tounge, i have the notes somewhere around here...
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08-06-2009, 07:49 PM | #4 |
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08-06-2009, 07:53 PM | #6 |
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08-06-2009, 08:38 PM | #7 |
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its a power series. You may want to look into this website:
http://appsci.queensu.ca/courses/APS...ments/nops.pdf but to simple things out, here's a general equation that you can use c/(1-x) where c is 5 in this case, and x is 1/(x+1) and something like that. and that is as far as I remember from my calculus class...lol ________ Portuguese recipes ________ VAPIR NO2 ________ fat woman Cams ________ The cigar boss Last edited by OverDrive; 04-14-2011 at 10:53 PM.. |
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08-07-2009, 12:35 AM | #10 | |
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1 + 1/(n^1) + 1/(n^2) + 1/(n^3) ... 1/n^N = 1 / ( 1 - ( 1 / n)) i.e. 1 + 1/2 + 1/4 + 1/8 + 1/16 + ... = 1 / (1 - ( 1 / 2 )) = 2 I'm just taking a stab at what you're looking for/remembering. The series you posted terminates, so I'm not sure what you're looking for. |
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08-07-2009, 01:09 AM | #11 |
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Radix you got it haha thanks for all the replies. Actually nah it was something I came up while my friend's younger sis was doing her school work and it just seemed so familiar lol but I don't remember anything from high school too much football
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08-07-2009, 02:06 AM | #16 |
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08-07-2009, 02:33 AM | #18 |
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i go make a fry's run around noon then proceed to take lunch. i take a lot of cigarette breaks, but i'm doing 5x what the old IT guy did. i've been working late because there are a lot of OE's during business hours, and i'm not a huge fan, but i don't like waking up early anyway.
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08-07-2009, 03:17 AM | #20 |
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i think its called mathematical induction. you replace the X with 1 then prove it, then replace x with k and prove it, then replace x with k+1 and prove it. if all the proofs work out then there you go.
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08-07-2009, 03:20 AM | #21 |
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Mathematical induction is used to prove that a mathematical statement is true. What he wanted was a shortcut for the summation of a geometric series.
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08-07-2009, 03:28 AM | #22 | |
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so i pulled out my notes and found this formula under geometric series 1x1-r^n / 1-r |
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