meowowowow

[endofanera7]

[aut0sh0cker]

Originally Posted by endofanera7

you crossed the bottom middle segment twice... sorry

[endofanera7]

Originally Posted by aut0sh0cker

you crossed the bottom middle segment twice... sorry

FUKIN BITCH!

[oldaccount]

Originally Posted by endofanera7

FUKIN BITCH!

i did the same thing. thought i had it, but crossed the same segment twice.

[endofanera7]

Originally Posted by Suareezay

i did the same thing. thought i had it, but crossed the same segment twice.

what about this?

[radix]

Some of my previous posts were made from my G1, so my options were practically somewhat limited. Now that I'm home again, it's easier to post, and to google as well as reference my math texts, so here goes...

If you look at the puzzle as having eight line segments, then the problem is solvable, and my solution is correct. My point is simple. Line segment intersections don't necessarily create new line segments, as a line segment is defined by endpoints, which can be any points on a line that you choose. I.e. the following picture has only two line segments, not four:




If you really want to get technical, since a point occupies no space, and there are an infinite number of points on a line between any two points, it then follows logically that if any two points on a line or line segment are chosen as endpoints, then there are an infinite number of line segments within any one line segment. For practical purposes I see two line segments in the picture above, and eight in John's diagram. If you do not accept that there are only eight line segments in the puzzle then the puzzle is not solvable:

http://en.wikipedia.org/wiki/Walls_&_Lines

The proof is as follows: "A continuous line that enters and leaves one of the rectangular rooms must of necessity cross two walls. Since the three bigger rooms have each an odd number of walls to be crossed, it follows that an end of a line must be inside each if all the 16 walls are crossed. But a continuous line has only two ends, so the puzzle is unsolvable."

there are other "outside the box" methods of solving it, such as this (see #161):

http://www.puzzles.com/PuzzleHelp/Pu...ems157_168.htm

but again, they require some sort of outside the box thinking. Note also that the verbiage used in outlining the task the solver is to accomplish varies widely.

[nnnnnnnnnnnnnnnnnnnnnn]

fuck this! I say we ban the OP for all of this.

[TK-421]

Originally Posted by ferrari355fi

fuck this! I say we ban the OP for all of this.

I second

Fuck this shit. This was the last thread I was going to read before going to sleep, but all this did was piss me off because I'm kinda-sorta-retarded-not-really. Now I'm going to fall asleep mad and wake up with a rash of frustration or something.


By the power of Grayskull, I BAN the OP!

[jhv]

[nnnnnnnnnnnnnnnnnnnnnn]

no that doesn't count. Fuck you, you are banned.

[jhv]

Originally Posted by ferrari355fi

fuck this! I say we ban the OP for all of this.

Originally Posted by news 4 u

I second

Fuck this shit. This was the last thread I was going to read before going to sleep, but all this did was piss me off because I'm kinda-sorta-retarded-not-really. Now I'm going to fall asleep mad and wake up with a rash of frustration or something.


By the power of Grayskull, I BAN the OP!

[jhv]

Originally Posted by ferrari355fi

no that doesn't count. Fuck you, you are banned.

of course if counts. go kill yourself.

[oldaccount]

fuck this game.

[endofanera7]

[Blake]

Originally Posted by ferrari355fi

no that doesn't count. Fuck you, you are banned.

[radix]

Originally Posted by jh valley

Attachment 239580

I don't think that works...

A---------------------C------------------------B
|                     |                        |
|                     |                        |

AB here is, after all, still a line segment as defined by endpoints A and B, and you've intersected it twice.

[TK-421]

I think everyone in this thread should be banned. There's enough on this page to go around

[jhv]

Originally Posted by anmcguire

I don't think that works...

A---------------------C------------------------B
|                     |                        |
|                     |                        |

AB here is, after all, still a line segment as defined by endpoints A and B, and you've intersected it twice.

fucking andrew, i thought i had it. i only accounted for the smaller segments FFFFFFFFFFFFFFUUUUUUUUUUUUU-

[radix]

Originally Posted by jh valley

fucking andrew, i thought i had it. i only accounted for the smaller segments FFFFFFFFFFFFFFUUUUUUUUUUUUU-

Sorry John... That's why I said that you have to accept there are only eight line segments in the diagram or accept that there is no adequate solution as per the links I posted.

[nnnnnnnnnnnnnnnnnnnnnn]

ban ban ban

[jhv]

Originally Posted by anmcguire

Sorry John... That's why I said that you have to accept there are only eight line segments in the diagram or accept that there is no adequate solution as per the links I posted.

its all good, /b/ro

[Year's_End]

how the hell did this serious thread get so big lol

serious shit man.